Обсуждение настройки и работы сервисов, резервирования, сетевых настроек и вопросов безопасности ОС для молодых и начинающих системных администраторов.
да и еще вопросик заодно уж
в вебмине вижу следующее
Максимальное число зарезервированных процессов сервера 20
Число начальных процессов сервера 8
не многовато ли 20 процессов апача? ^^
start(){
touch "$errlogfile"
chown mysql:mysql "$errlogfile"
chmod 0640 "$errlogfile"
[ -x /sbin/restorecon ] && /sbin/restorecon "$errlogfile"
if [ ! -d "$datadir/mysql" ]; then
# First, make sure $datadir is there with correct permissions
if [ ! -e "$datadir" -a ! -h "$datadir" ]
then
mkdir -p "$datadir" || exit 1
fi
chown mysql:mysql "$datadir"
chmod 0755 "$datadir"
[ -x /sbin/restorecon ] && /sbin/restorecon "$datadir"
# Now create the database
action $"Initializing MySQL database: " /usr/bin/mysql_install_db --datadir="$datadir" --user=mysql
ret=$?
chown -R mysql:mysql "$datadir"
if [ $ret -ne 0 ]; then
return $ret
fi
fi
chown mysql:mysql "$datadir"
chmod 0755 "$datadir"
# Pass all the options determined above, to ensure consistent behavior.
# In many cases mysqld_safe would arrive at the same conclusions anyway
# but we need to be sure. (An exception is that we don't force the
# log-error setting, since this script doesn't really depend on that,
# and some users might prefer to configure logging to syslog.)
# Note: set --basedir to prevent probes that might trigger SELinux
# alarms, per bug #547485
/usr/bin/mysqld_safe --datadir="$datadir" --socket="$socketfile" \
--pid-file="$mypidfile" \
--basedir=/usr --user=mysql >/dev/null 2>&1 &
safe_pid=$!
# Spin for a maximum of N seconds waiting for the server to come up;
# exit the loop immediately if mysqld_safe process disappears.
# Rather than assuming we know a valid username, accept an "access
# denied" response as meaning the server is functioning.
ret=0
start(){
touch "$errlogfile"
chown mysql:mysql "$errlogfile"
chmod 0640 "$errlogfile"
[ -x /sbin/restorecon ] && /sbin/restorecon "$errlogfile"
if [ ! -d "$datadir/mysql" ]; then
# First, make sure $datadir is there with correct permissions
if [ ! -e "$datadir" -a ! -h "$datadir" ]
then
mkdir -p "$datadir" || exit 1
fi
chown mysql:mysql "$datadir"
chmod 0755 "$datadir"
[ -x /sbin/restorecon ] && /sbin/restorecon "$datadir"
# Now create the database
action $"Initializing MySQL database: " /usr/bin/mysql_install_db --datadir="$datadir" --user=mysql
ret=$?
chown -R mysql:mysql "$datadir"
if [ $ret -ne 0 ]; then
return $ret
fi
fi
chown mysql:mysql "$datadir"
chmod 0755 "$datadir"
# Pass all the options determined above, to ensure consistent behavior.
# In many cases mysqld_safe would arrive at the same conclusions anyway
# but we need to be sure. (An exception is that we don't force the
# log-error setting, since this script doesn't really depend on that,
# and some users might prefer to configure logging to syslog.)
# Note: set --basedir to prevent probes that might trigger SELinux
# alarms, per bug #547485
/usr/bin/mysqld_safe --datadir="$datadir" --socket="$socketfile" \
--pid-file="$mypidfile" \
--basedir=/usr --user=mysql >/dev/null 2>&1 &
safe_pid=$!
# Spin for a maximum of N seconds waiting for the server to come up;
# exit the loop immediately if mysqld_safe process disappears.
# Rather than assuming we know a valid username, accept an "access
# denied" response as meaning the server is functioning.
ret=0
STARTTIMEOUT=120
while [ $STARTTIMEOUT -gt 0 ]; do
RESPONSE=`/usr/bin/mysqladmin --socket="$socketfile" --user=UNKNOWN_MYSQL_USER ping 2>&1` && break
echo "$RESPONSE" | grep -q "Access denied for user" && break
if ! /bin/kill -0 $safe_pid 2>/dev/null; then
echo "MySQL Daemon failed to start."
ret=1
break
fi
sleep 1
let STARTTIMEOUT=${STARTTIMEOUT}-1
done
if [ $STARTTIMEOUT -eq 0 ]; then
echo "Timeout error occurred trying to start MySQL Daemon."
ret=1
fi
if [ $ret -eq 0 ]; then
action $"Starting $prog: " /bin/true
touch /var/lock/subsys/mysqld
else
action $"Starting $prog: " /bin/false
fi
return $ret
}
STARTTIMEOUT=120
while [ $STARTTIMEOUT -gt 0 ]; do
RESPONSE=`/usr/bin/mysqladmin --socket="$socketfile" --user=UNKNOWN_MYSQL_USER ping 2>&1` && break
echo "$RESPONSE" | grep -q "Access denied for user" && break
if ! /bin/kill -0 $safe_pid 2>/dev/null; then
echo "MySQL Daemon failed to start."
ret=1
break
fi
sleep 1
let STARTTIMEOUT=${STARTTIMEOUT}-1
done
if [ $STARTTIMEOUT -eq 0 ]; then
echo "Timeout error occurred trying to start MySQL Daemon."
ret=1
fi
if [ $ret -eq 0 ]; then
action $"Starting $prog: " /bin/true
touch /var/lock/subsys/mysqld
else
action $"Starting $prog: " /bin/false
fi
return $ret
}